(3x^2-5)=4x^2

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Solution for (3x^2-5)=4x^2 equation: 



(3x^2-5)=4x^2

We move all terms to the left:

(3x^2-5)-(4x^2)=0

determiningTheFunctionDomain
-4x^2+(3x^2-5)=0

We get rid of parentheses

-4x^2+3x^2-5=0

We add all the numbers together, and all the variables

-1x^2-5=0

a = -1; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-1)·(-5)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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